# Solution

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The series resistor and the control lamp are connected in series. The following applies to the total voltage: $Utotal=R.Series resistor⋅I.Max+ULamp.$ One redeems $R.Series resistor$ on, then you get $R.Series resistor=Utotal−ULampI.Max=230V-130 V20 mA=5000$ Ω.