Chemistry

Sample calculations for the geometry of the double tube heat exchanger

Sample calculations for the geometry of the double tube heat exchanger


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Tab. 1
Given:
Outer tubedaa= 11.5 mmdia= 9.5 mm
Inner tubedai= 7.5 mmdii= 5.5 mm
Tab. 2
Cold water circuit
Area of ​​the annulusEntire (wetted) perimeterEquivalent diameter
A.q=((dia2)2(dai2)2)πU=(dai2)2π+(dia2)2πdeq=4A.qU
A.q=((9,5mm2)2(7,5mm2)2)πU=(7,5mm2)2π+(9,5mm2)2πdeq=426,70mm253,40mm
A.q= 26.70 mm2U = 53.40 mmdeq= 2 mm
Tab. 3
Hot water circuit
Area of ​​the circleEntire (wetted) perimeterEquivalent diameter
A.q=(dii2)2πU=(dii2)2πdeq=4A.qU
A.q=(5,5mm2)2πU=(5,5mm2)2πdeq=423,76mm217,28mm
A.q= 23.76 mm2U = 17.28 mmdeq= 5.5 mm

Since the warm water flows through the inner pipe, the equivalent diameter in the experiment corresponds to the inner diameter of the inner pipe deq= dii= 5.5 mm. This calculation and that of the wetted area is not absolutely necessary.


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